Which one of the following complexes will con | vedclass

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(D) The consumption of $AgNO_3$ depends on the number of ionizable $Cl^-$ ions present outside the coordination sphere.$Na_2[CrCl_5(H_2O)]$ provides $

Vedclass · Accepted Answer

$[Cr(H_2O)_6]Cl_3$

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(D) The consumption of $AgNO_3$ depends on the number of ionizable $Cl^-$ ions present outside the coordination sphere.$Na_2[CrCl_5(H_2O)]$ provides $0$ ionizable $Cl^-$ ions.$Na_3[CrCl_6]$ provides $0$ ionizable $Cl^-$ ions.$[Cr(H_2O)_5Cl]Cl_2$ provides $2$ ionizable $Cl^-$ ions.$[Cr(H_2O)_6]Cl_3$ provides $3$ ionizable $Cl^-$ ions.Since $[Cr(H_2O)_6]Cl_3$ furnishes the highest number of $Cl^-$ ions ($3$ moles per mole of complex),it will consume the most equivalents of $AgNO_3$.

Which one of the following complexes will consume more equivalents of aqueous solution of $AgNO_3$?

Similar Questions

The molecular formula of a coordination complex is $CoH_{12}O_6Cl_3$. When one mole of this aqueous solution of the complex is reacted with an excess of aqueous $AgNO_3$ solution,$3$ moles of $AgCl$ are formed. What is the correct formula of the complex?

Homoleptic complexes among the following are:
$(A)$ $K_3[Al(C_2O_4)_3]$
$(B)$ $[CoCl_2(en)_2]^{+}$
$(C)$ $K_2[Zn(OH)_4]$

The coordination number of chromium in $K[Cr(H_2O)_2(C_2O_4)_2]$ is

Which one of the following forms a complex with an excess of $CN^{-}$ (cyanide) having a coordination number of two?

An example of a double salt is:

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