Which one of the following compounds forms a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Amines react with alkyl halides in excess to undergo exhaustive alkylation,resulting in the formation of a quaternary ammonium salt.Among the give

Vedclass · Accepted Answer

$C_6H_5NH_2$

Vedclass · Answer

(C) Amines react with alkyl halides in excess to undergo exhaustive alkylation,resulting in the formation of a quaternary ammonium salt.Among the given options,$C_6H_5NH_2$ (aniline) is an amine,which reacts with excess methyl iodide $(CH_3I)$ to form a quaternary ammonium salt as shown below:$C_6H_5NH_2 + 3CH_3I \rightarrow C_6H_5N^+(CH_3)_3I^- + 2HI$Ethers ($C_2H_5OCH_3$ and $(CH_3)_2CHOC_2H_5$) do not form quaternary salts under these conditions,and nitro compounds $(C_6H_5NO_2)$ are not nucleophilic enough to undergo this reaction.

Which one of the following compounds forms a quaternary salt on reacting with excess methyl iodide?

Similar Questions

$A$. Phenyl methanamine
$B$. $N,N$-Dimethylaniline
$C$. $N$-Methylaniline
$D$. Benzenamine
Choose the correct order of basic nature of the above amines.

In the following reaction,the product $(A)$ is

In the following reactions,the major product $W$ is

Aromatic primary amine when treated with cold $HNO_2$ gives

The compound obtained by the reaction between primary amine and aldehyde is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module