Which one of the following conversions involves a change in both hybridisation and shape?

  • A
    $CH_{4} \longrightarrow C_{2}H_{6}$
  • B
    $NH_{3} \longrightarrow NH_{4}^{+}$
  • C
    $BF_{3} \longrightarrow BF_{4}^{-}$
  • D
    $H_{2}O \longrightarrow H_{3}O^{+}$

Explore More

Similar Questions

Sodium bicarbonate $(NaHCO_3)$ has:

What are the successes and failures of the Lewis theory in explaining chemical bonding?

The number of electrons in the valence shell of the central atom of a molecule is $8$. The molecule is

$A$ tin chloride $Q$ undergoes the following reactions (not balanced):
$Q + Cl^{-} \rightarrow X$
$Q + Me_3N \rightarrow Y$
$Q + CuCl_2 \rightarrow Z + CuCl$
$X$ is a monoanion having pyramidal geometry. Both $Y$ and $Z$ are neutral compounds. Choose the correct option$(s)$.
$(1)$ The central atom in $X$ is $sp^3$ hybridized
$(2)$ The oxidation state of the central atom in $Z$ is $+4$
$(3)$ The central atom in $Z$ has no lone pair of electrons
$(4)$ There is a coordinate bond in $Y$

Match the following molecules in Column $I$ with the number of lone pairs on their central atom in Column $II$.
Column $I$ (Molecules)Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$$1. \ \text{Two}$
$B. \ H_2O$$2. \ \text{Three}$
$C. \ XeF_2$$3. \ \text{Zero}$
$D. \ CH_4$$4. \ \text{Four}$
$5. \ \text{One}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo