Which one of the following solutions will have the highest conductivity?

The specific conductivity of a normal solution of $KCl$ at $25 \, ^oC$ is $0.002765 \, S \, cm^{-1}$. If the resistance of the cell is $400 \, \Omega$,what is the cell constant (in $cm^{-1}$)?

At a particular temperature,the ratio of molar conductance to specific conductance of $0.01 \ M$ $NaCl$ solution is

Equivalent conductances of $BaCl_2$,$H_2SO_4$ and $HCl$ at infinite dilution are $\Lambda_1^\infty$,$\Lambda_2^\infty$ and $\Lambda_3^\infty$ respectively. Then,the equivalent conductance of $BaSO_4$ at infinite dilution will be:

If the conductance and specific conductance of a solution are both $1$,then its cell constant would be:

Limiting molar conductivity of $NH_4OH$ [i.e.,$\Lambda ^o_{m(NH_4OH)}$] is equal to: