Which of the following statements are correct | vedclass

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(B, C) The correct statements are $(B)$ and $(C)$.Step $1$: The electronic configuration of $O_{2}^{2-}$ (total $18$ electrons) is: $\sigma 1s^{2}, \s

Vedclass · Accepted Answer

It has a bond order of $1$

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(B, C) The correct statements are $(B)$ and $(C)$.Step $1$: The electronic configuration of $O_{2}^{2-}$ (total $18$ electrons) is: $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, (\pi 2p_{x}^{2} = \pi 2p_{y}^{2}), (\pi^{*} 2p_{x}^{2} = \pi^{*} 2p_{y}^{2})$.Step $2$: Bond order $= \frac{1}{2} (N_b - N_a)$, where $N_b$ is the number of bonding electrons and $N_a$ is the number of anti-bonding electrons.Step $3$: $N_b = 10$ and $N_a = 8$. Thus, $BO = \frac{10 - 8}{2} = \frac{2}{2} = 1$. So, statement $(C)$ is correct.Step $4$: Since all electrons are paired, the ion is diamagnetic. So, statement $(B)$ is correct.Step $5$: $O_{2}^{2-}$ has $18$ electrons, while neon $(Ne)$ has $10$ electrons. Thus, they are not isoelectronic.

Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?

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