Which term of the A.P. 83, 77, 71, ldots is i | vedclass

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(A) The given $A.P.$ is $83, 77, 71, \ldots$Here,the first term $a = 83$ and the common difference $d = 77 - 83 = -6$.We want to find the first negati

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) The given $A.P.$ is $83, 77, 71, \ldots$Here,the first term $a = 83$ and the common difference $d = 77 - 83 = -6$.We want to find the first negative term,so we set the $n^{th}$ term $a_n The formula for the $n^{th}$ term is $a_n = a + (n - 1)d$.Substituting the values: $83 + (n - 1)(-6) $83 - 6n + 6 $89 - 6n $89 $n > \frac{89}{6}$$n > 14.833...$Since $n$ must be an integer,the smallest integer greater than $14.833$ is $n = 15$.Therefore,the $15^{th}$ term is the first negative term.

Which term of the $A.P.$ $83, 77, 71, \ldots$ is its first negative term (in $^{th}$)?

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