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(C) $T$ is a lactone (cyclic ester). Esters undergo hydrolysis in hot aqueous $NaOH$ to form the corresponding carboxylate salt and alcohol,making the

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$B, C, D$

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(C) $T$ is a lactone (cyclic ester). Esters undergo hydrolysis in hot aqueous $NaOH$ to form the corresponding carboxylate salt and alcohol,making them soluble. Thus,statement $A$ is correct.$U$ is $3$-methylpentane-$1,5$-diol. It has a chiral center at the $C3$ position,so it is optically active. Thus,statement $B$ is correct.$V$ is $3$-methylpentanedioic acid. Carboxylic acids react with $NaHCO_3$ to release $CO_2$ gas,causing effervescence. Thus,statement $D$ is correct.$W$ is the diacetate of $U$. The structure of $U$ is $C_6H_{14}O_2$. Acetylation replaces two $H$ atoms with two $CH_3CO$ groups $(C_2H_2O)$,adding $C_4H_4O_2$ and removing $2H$. The formula of $W$ is $C_{10}H_{18}O_4$. Thus,statement $C$ is correct.Therefore,all statements $A, B, C, D$ are correct. However,based on the options provided,the most appropriate choice is $C$.

With reference to the scheme given,which of the given statement$(s)$ about $T$,$U$,$V$ and $W$ is (are) correct?
$A$. $T$ is soluble in hot aqueous $NaOH$
$B$. $U$ is optically active
$C$. Molecular formula of $W$ is $C_{10}H_{18}O_4$
$D$. $V$ gives effervescence on treatment with aqueous $NaHCO_3$

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With reference to the scheme given,which of the given statement$(s)$ about $T$,$U$,$V$ and $W$ is (are) correct?$A$. $T$ is soluble in hot aqueous $NaOH$$B$. $U$ is optically active$C$. Molecular formula of $W$ is $C_{10}H_{18}O_4$$D$. $V$ gives effervescence on treatment with aqueous $NaHCO_3$