With the help of the remainder theorem,find t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $x - 4$,so $a = 4$.To find the remainder,we calculate $p(4)$:$p(4) = (4)^{3} + (4)^{2} - 26(4) + 24$$p(4) = 64 + 16 - 104 + 24$$p(4) = 80 - 104 + 24$$p(4) = -24 + 24 = 0$.Therefore,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 4$.

Similar Questions

Factorise the following quadratic polynomial by splitting the middle term: $12x^2 + 23x + 5$.

Examine whether $x+2$ is a factor of $x^{3}+3x^{2}+5x+6$ and of $2x+4$.

Check whether the polynomial $q(t) = 4t^3 + 4t^2 - t - 1$ is a multiple of $2t + 1$.

Factorise:
$x^{2}+9x+18$

Check whether the polynomial $p(x) = x^{3} + 9x^{2} + 26x + 24$ is a multiple of $x + 2$ or not.

Vedclass Test Series

Exam Paper Generator

Online Exam Module