(A) We use the formula: $\frac{M_{1} \times D_{1} \times t_{1}}{W_{1}} = \frac{M_{2} \times D_{2} \times t_{2}}{W_{2}}$Given:$M_{1} = 24, D_{1} = 27,

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(A) We use the formula: $\frac{M_{1} \times D_{1} \times t_{1}}{W_{1}} = \frac{M_{2} \times D_{2} \times t_{2}}{W_{2}}$Given:$M_{1} = 24, D_{1} = 27, t_{1} = 7, W_{1} = 1$$M_{2} = 14, D_{2} = ?, t_{2} = 9, W_{2} = 1$Substituting the values:$24 \times 27 \times 7 = 14 \times D_{2} \times 9$$D_{2} = \frac{24 \times 27 \times 7}{14 \times 9}$$D_{2} = \frac{24 \times 3 \times 7}{14}$$D_{2} = \frac{24 \times 3}{2} = 12 \times 3 = 36$Therefore,$14$ men will complete the work in $36$ $\text{days}$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

Working $7\, \text{hours}$ daily,$24$ men can complete a piece of work in $27$ $\text{days}$. In how many $\text{days}$ would $14$ men complete the same piece of work working $9\, \text{hours}$ daily?

A
$36$
B
$30$
C
$32$
D
None of these

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Time and Work and Wages

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Time and Work

$A$ can do a piece of work in $12$ days and $B$ in $20$ days. If they together work on it for $5$ days and the remaining work is completed by $C$ in $3$ days, then in how many days can $C$ do the same work alone?

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$A$ can do $\frac{1}{3}$ of a work in $5 \text{ days}$ and $B$ can do $\frac{2}{5}$ of the work in $10 \text{ days}$. In how many $\text{days}$ can both $A$ and $B$ together do the work?

Medium

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$A$ alone can complete a work in $18 \, days$ and $B$ alone in $15 \, days.$ $B$ alone worked at it for $10 \, days$ and then left the work. In how many more days will $A$ alone complete the remaining work?

Medium

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$A$ and $B$ together can complete a work in $12$ days. $A$ alone can complete it in $20$ days. If $B$ does the work only for half a day daily,then in how many days will $A$ and $B$ together complete the work?

Medium

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$X$ and $Y$ can do a piece of work in $20$ days and $12$ days respectively. $X$ started the work alone and then after $4$ days $Y$ joined him until the completion of the work. How long did the work last? (in days)

Medium

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Working $7\, \text{hours}$ daily,$24$ men can complete a piece of work in $27$ $\text{days}$. In how many $\text{days}$ would $14$ men complete the same piece of work working $9\, \text{hours}$ daily?

Similar Questions

$A$ can do a piece of work in $12$ days and $B$ in $20$ days. If they together work on it for $5$ days and the remaining work is completed by $C$ in $3$ days, then in how many days can $C$ do the same work alone?

$A$ can do $\frac{1}{3}$ of a work in $5 \text{ days}$ and $B$ can do $\frac{2}{5}$ of the work in $10 \text{ days}$. In how many $\text{days}$ can both $A$ and $B$ together do the work?

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