Write about the dual behaviour of matter.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) de-Broglie principle: The French physicist,de-Broglie,in $1924$ proposed that matter,like radiation,should also exhibit dual behaviour,i.e.,both particle and wavelike properties.
This means that just as the photon has momentum as well as wavelength,electrons should also have momentum as well as wavelength.
Analogy of de-Broglie principle: The following relation exists between wavelength $(\lambda)$ and momentum $(p)$ of a material particle:
$\lambda = \frac{h}{mv} = \frac{h}{p} \quad (Eq. -2.30)$
Proof of de-Broglie's dual behaviour: de-Broglie's prediction was confirmed experimentally when it was found that an electron beam undergoes diffraction,a phenomenon characteristic of waves.
Limitation: According to de-Broglie,every object in motion has a wave character. The wavelengths associated with ordinary objects are so short (because of their large masses) that their wave properties cannot be detected.
The wavelengths associated with electrons and other subatomic particles (with very small mass) can,however,be detected experimentally.

Explore More

Similar Questions

The ratio of de Broglie wavelengths of two particles,having mass ratio $1 : 3$ and kinetic energy ratio $2 : 1$ is

Which of the following relations is correct, if the wavelength $(\lambda)$ is equal to the distance travelled by the electron in one second? $h$ is the Planck's constant and $m$ is the mass of electron.

If the mass of particle $B$ is four times the mass of particle $A$ and the velocity of particle $A$ is eight times the velocity of particle $B$,then the ratio of the de Broglie wavelength of particle $A$ to particle $B$ will be .......

Difficult
View Solution

The de Broglie wavelength of a particle $X$ moving with a certain velocity is $1 \ \mathring{A}$. If the mass of $Y$ is $25\%$ of $X$ and its velocity is $75\%$ of $X$,then the de Broglie wavelength of $Y$ will be ........... $\mathring{A}$.

If the de Broglie wavelength of an electron is $728.14 \ nm$,its kinetic energy in $J$ is: (mass of electron $= 9.1 \times 10^{-31} \ kg$; $h = 6.626 \times 10^{-34} \ J \ s$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo