Write the chemical reaction to prepare inorganic benzene $(B_3N_3H_6)$.

(N/A) The preparation of inorganic benzene (borazine) involves the reaction of diborane with ammonia at high temperatures:
$3 B_2H_6 + 6 NH_3 \rightarrow 2 B_3N_3H_6 + 12 H_2$
Alternatively,it can be represented as a two-step process:
$3 B_2H_6 + 6 NH_3$ $\rightarrow 3 [BH_2(NH_3)_2]^+ [BH_4]^-$ $\xrightarrow{\Delta} 2 B_3N_3H_6 + 12 H_2$