Medium
Write the general reaction and its rate law.
(N/A) For a general chemical reaction where reactants $A$ and $B$ form products $P$ with stoichiometric coefficients $a$ and $b$:
$aA + bB \rightarrow \text{Products}$
The rate law for this reaction is expressed as:
$Rate = k[A]^x[B]^y$
Where:
$1. k$ is the rate constant.
$2. [A]$ and $[B]$ are the molar concentrations of the reactants.
$3. x$ and $y$ are the orders of the reaction with respect to reactants $A$ and $B$,respectively,which may or may not be equal to the stoichiometric coefficients $a$ and $b$.
$aA + bB \rightarrow \text{Products}$
The rate law for this reaction is expressed as:
$Rate = k[A]^x[B]^y$
Where:
$1. k$ is the rate constant.
$2. [A]$ and $[B]$ are the molar concentrations of the reactants.
$3. x$ and $y$ are the orders of the reaction with respect to reactants $A$ and $B$,respectively,which may or may not be equal to the stoichiometric coefficients $a$ and $b$.
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Similar Questions
For the decomposition of a compound $AB$ at $600 \ K$,the following data were obtained:
$[AB] \ (mol \ dm^{-3})$ Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$ $0.20$ $2.75 \times 10^{-8}$ $0.40$ $11.0 \times 10^{-8}$ $0.60$ $24.75 \times 10^{-8}$
The order for the decomposition of $AB$ is:
| $[AB] \ (mol \ dm^{-3})$ | Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$ |
| $0.20$ | $2.75 \times 10^{-8}$ |
| $0.40$ | $11.0 \times 10^{-8}$ |
| $0.60$ | $24.75 \times 10^{-8}$ |
The order for the decomposition of $AB$ is:
DifficultKCET 2009
View SolutionConsider the following single step reaction in gas phase at constant temperature.
$2 \ A_{(g)} + B_{(g)} \rightarrow C_{(g)}$
The initial rate of the reaction is recorded as $r_1$ when the reaction starts with $1.5 \ atm$ pressure of $A$ and $0.7 \ atm$ pressure of $B$. After some time,the rate $r_2$ is recorded when the pressure of $C$ becomes $0.5 \ atm$. The ratio $r_1 : r_2$ is $\qquad$ $\times 10^{-1}$.
(Nearest integer)
$2 \ A_{(g)} + B_{(g)} \rightarrow C_{(g)}$
The initial rate of the reaction is recorded as $r_1$ when the reaction starts with $1.5 \ atm$ pressure of $A$ and $0.7 \ atm$ pressure of $B$. After some time,the rate $r_2$ is recorded when the pressure of $C$ becomes $0.5 \ atm$. The ratio $r_1 : r_2$ is $\qquad$ $\times 10^{-1}$.
(Nearest integer)
For the reaction: $2 A + B \rightarrow A_2 B$,the rate $= k[A][B]^2$ with $k = 2.0 \times 10^{-6} \ mol^{-2} \ L^2 \ s^{-1}$. Calculate the initial rate of the reaction when $[A] = 0.1 \ mol \ L^{-1}$ and $[B] = 0.2 \ mol \ L^{-1}$. Calculate the rate of reaction after $[A]$ is reduced to $0.06 \ mol \ L^{-1}$.
Difficult
View SolutionThe mechanism of the reaction $A + 2B \to D$ is
$2B \xrightarrow{k} B_2$ $[Slow]$
$B_2 + A \to D$ $[Fast]$
The rate law expression,order with respect to $A$,order with respect to $B$ and overall order of reaction are respectively
$2B \xrightarrow{k} B_2$ $[Slow]$
$B_2 + A \to D$ $[Fast]$
The rate law expression,order with respect to $A$,order with respect to $B$ and overall order of reaction are respectively
Medium
View SolutionThe rate law for the reaction $A + B \rightarrow P$ is given by $\text{rate} = k[A]^2[B]$. The rate constant of the reaction at $300 \text{ K}$ is $6.0 \text{ M}^{-2} \text{s}^{-1}$. Calculate the rate of the reaction when $[A] = 1 \text{ M}$ and $[B] = 0.2 \text{ M}$. (in $\text{ M s}^{-1}$)
DifficultMHT CET 2026
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