Write the converse of the following statement:
If two integers $a$ and $b$ are such that $a > b$,then $a - b$ is always a positive integer.
If two integers $a$ and $b$ are such that $a > b$,then $a - b$ is always a positive integer.
(N/A) The converse of a statement of the form "If $P$,then $Q$" is "If $Q$,then $P$.
Here,$P$ is "two integers $a$ and $b$ are such that $a > b$" and $Q$ is "$a - b$ is always a positive integer".
Therefore,the converse is: "If $a - b$ is always a positive integer,then two integers $a$ and $b$ are such that $a > b$."
Here,$P$ is "two integers $a$ and $b$ are such that $a > b$" and $Q$ is "$a - b$ is always a positive integer".
Therefore,the converse is: "If $a - b$ is always a positive integer,then two integers $a$ and $b$ are such that $a > b$."
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