Write the Arrhenius equation representing the relationship between the rate constants $k_1$ and $k_2$ at two different temperatures $T_1$ and $T_2$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The Arrhenius equation at two different temperatures is given by: $\log \frac{k_2}{k_1} = \frac{E_a}{2.303R} [\frac{T_2 - T_1}{T_1 T_2}]$
Where:
$k_1$ and $k_2$ are the rate constants at temperatures $T_1$ and $T_2$ respectively.
$E_a$ is the activation energy.
$R$ is the universal gas constant.

Explore More

Similar Questions

Which of the following statements is true for a catalyst?

The minimum energy required for molecules to enter into the reaction is called

When temperature is increased from $27\,{}^{\circ}C$ to $127\,{}^{\circ}C$,the rate of reaction becomes doubled. The activation energy $E_a$ will be ........ $kCal$.

Which of the following plots is in accordance with the Arrhenius equation?

For a reaction,the graph of $\ln k$ (on y-axis) and $1 / T$ (on x-axis) is a straight line with a slope $-2 \times 10^4 \ K$. The activation energy of the reaction (in $kJ \ mol^{-1}$) is $(R = 8.3 \ J \ K^{-1} \ mol^{-1})$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo