Write the formula of the product formed when the element $A$ (atomic number $19$) combines with the element $B$ (atomic number $17$). Draw its electronic dot structure. What is the nature of the bond formed?

(N/A) $1$. Identification of elements: Element $A$ has atomic number $19$, which is Potassium $(K)$. Its electronic configuration is $2, 8, 8, 1$. Element $B$ has atomic number $17$, which is Chlorine $(Cl)$. Its electronic configuration is $2, 8, 7$.
$2$. Formation of the product: Element $A$ loses $1$ electron to achieve a stable octet, forming $A^+$ ion. Element $B$ gains $1$ electron to achieve a stable octet, forming $B^-$ ion. The formula of the product is $AB$ (Potassium Chloride, $KCl$).
$3$. Electronic dot structure: $A \cdot + \cdot \dot{B} \cdot \rightarrow [A]^+ [:\ddot{B}:]^-$.
$4$. Nature of the bond: Since the bond is formed by the complete transfer of electrons from a metal to a non-metal, it is an ionic bond.