Write a note on the isochoric process.

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(N/A) The process during which the volume of a system remains constant is known as an isochoric process. In an isochoric process,the volume $V$ is constant.
Since work $W = P \Delta V$ and $\Delta V = 0$,the work done $W = 0$.
According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Since $\Delta W = 0$,we have $\Delta Q = \Delta U$.
This implies that if heat is absorbed,the internal energy increases,leading to an increase in temperature. Conversely,if the gas rejects heat,the internal energy decreases,leading to a decrease in temperature.
The change in temperature for a given amount of heat can be determined by the specific heat capacity of the gas at constant volume using the formula:
$C_v = \frac{\Delta Q}{\mu \Delta T} \implies \Delta T = \frac{\Delta Q}{\mu C_v}$,where $\mu$ is the number of moles.

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An ideal gas goes from an initial state to a final state. During the process,the pressure of the gas increases linearly with temperature. Which of the following statements are correct?
$A.$ The work done by the gas during the process is zero.
$B.$ The heat added to the gas is different from the change in its internal energy.
$C.$ The volume of the gas is increased.
$D.$ The internal energy of the gas is increased.
$E.$ The process is isochoric (constant volume process).
Choose the correct answer from the options given below $:-$

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