Write the set builder form of the set $ A = \{-1, 1\} $.
- A$ A = \{x : x \text{ is a real number} \} $
- B$ A = \{x : x \text{ is an integer} \} $
- C$ A = \{x : x \text{ is a root of the equation } x^{2} = 1\} $
- D$ A = \{x : x \text{ is a root of the equation } x^{2} + 1 = 0\} $
Explore More
Similar Questions
The set $A = \{ x : x \in \mathbb{R}, x^2 = 16 \text{ and } 2x = 6 \}$ is equal to
Medium
View SolutionLet $A = \{1, 2, 3, \ldots, 10\}$ and $B = \left\{\frac{m}{n} : m, n \in A, m < n \text{ and } \gcd(m, n) = 1\right\}$. Then $n(B)$ is equal to:
DifficultJEE MAIN 2025
View SolutionWhich of the following is a subset of every set?
Easy
View SolutionWrite the following set in the set-builder form: $\{ 5, 25, 125, 625 \}$
Easy
View SolutionList all the elements of the following set:
$A = \{ x:x \text{ is an odd natural number} \}$
$A = \{ x:x \text{ is an odd natural number} \}$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo