Write 'True' or 'False' and justify your answer.
$\sqrt{(1-\cos^2 \theta) \sec^2 \theta} = \tan \theta$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) True.
Given expression: $\sqrt{(1-\cos^2 \theta) \sec^2 \theta}$
Using the identity $\sin^2 \theta + \cos^2 \theta = 1$,we have $1 - \cos^2 \theta = \sin^2 \theta$.
Substituting this into the expression: $\sqrt{\sin^2 \theta \cdot \sec^2 \theta}$
Since $\sec \theta = \frac{1}{\cos \theta}$,we can write: $\sqrt{\sin^2 \theta \cdot \frac{1}{\cos^2 \theta}} = \sqrt{\frac{\sin^2 \theta}{\cos^2 \theta}}$
Using the identity $\tan \theta = \frac{\sin \theta}{\cos \theta}$,we get: $\sqrt{\tan^2 \theta} = \tan \theta$.
Thus,the statement is true.

Explore More

Similar Questions

Prove the following identity,where the angles involved are acute angles for which the expressions are defined:
$\frac{\tan \theta}{1-\cot \theta}+\frac{\cot \theta}{1-\tan \theta}=1+\sec \theta \operatorname{cosec} \theta$

Difficult
View Solution

Express the trigonometric ratios $\sin A$,$\sec A$,and $\tan A$ in terms of $\cot A$.

Difficult
View Solution

$\cos (40^{\circ}-\theta)-\sin (50^{\circ}+\theta) = \ldots \ldots \ldots \ldots$

If $\tan A = \cot B$,prove that $A + B = 90^{\circ}$.

Show that $\tan ^{4} \theta+\tan ^{2} \theta=\sec ^{4} \theta-\sec ^{2} \theta$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo