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(B) $PQRS$ is a parallelogram.We know that the diagonal $QS$ of a parallelogram divides it into two triangles of equal area.$	herefore \operatorname{

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False

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(B) $PQRS$ is a parallelogram.We know that the diagonal $QS$ of a parallelogram divides it into two triangles of equal area.$	herefore \operatorname{ar}(	riangle QRS) = \frac{1}{2} \operatorname{ar}(PQRS) = \frac{1}{2} 	imes 180 \, cm^{2} = 90 \, cm^{2}$.Since $A$ is any point on the diagonal $QS$,the triangle $	riangle ASR$ is contained within $	riangle QRS$ (or is a part of it).Specifically,$	riangle ASR$ and $	riangle QRS$ share the same base $SR$,but the height of $	riangle ASR$ with respect to base $SR$ is less than the height of $	riangle QRS$ with respect to the same base (unless $A$ coincides with $Q$).Therefore,$\operatorname{ar}(	riangle ASR) Thus,$\operatorname{ar}(	riangle ASR) Hence,the given statement is False.

Write True or False and justify your answer:
$PQRS$ is a parallelogram whose area is $180 \, cm^{2}$ and $A$ is any point on the diagonal $QS$. The area of $\triangle ASR = 90 \, cm^{2}$.

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Write True or False and justify your answer:$PQRS$ is a parallelogram whose area is $180 \, cm^{2}$ and $A$ is any point on the diagonal $QS$. The area of $\triangle ASR = 90 \, cm^{2}$.