A_{(g)} + B_{(g)} rightleftharpoons C_{(g)} + | vedclass

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(D) $1$. In the given energy profile diagram,curve $N$ represents the reaction without a catalyst,and curve $M$ represents the reaction with a catalys

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$P+Q$

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(D) $1$. In the given energy profile diagram,curve $N$ represents the reaction without a catalyst,and curve $M$ represents the reaction with a catalyst.$2$. The activation energy for the backward reaction is the energy difference between the transition state (peak of the curve) and the energy level of the products $(C+D)$.$3$. In the presence of a catalyst,the transition state is at the energy level corresponding to curve $M$.$4$. The energy level of the products $(C+D)$ is at a distance $P$ below the energy level of the reactants $(A+B)$.$5$. The energy level of the transition state for the catalyzed reaction $(M)$ is at a distance $Q$ above the reactants $(A+B)$.$6$. Therefore,the activation energy for the backward reaction in the presence of a catalyst is the sum of the energy difference between the products and reactants $(P)$ and the energy difference between the reactants and the catalyzed transition state $(Q)$,which is $P+Q$.

$A_{(g)} + B_{(g)} \rightleftharpoons C_{(g)} + D_{(g)}$
The curves $M$ and $N$ represent the variation of energy with reaction coordinate for the reaction in absence and presence of catalyst.
Which value represents the activation energy $(E_a)$ for the backward reaction in the presence of catalyst?

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$A_{(g)} + B_{(g)} \rightleftharpoons C_{(g)} + D_{(g)}$The curves $M$ and $N$ represent the variation of energy with reaction coordinate for the reaction in absence and presence of catalyst.Which value represents the activation energy $(E_a)$ for the backward reaction in the presence of catalyst?