CH_3-CH=CH_2 xrightarrow[reagent]{text{Bayer' | vedclass

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(D) $1$. Bayer's reagent $(1\% 	ext{ alkaline } KMnO_4)$ reacts with propene $(CH_3-CH=CH_2)$ to form propane$-1,2-$diol $(CH_3-CH(OH)-CH_2OH)$ as pr

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$(A)$ and $(B)$ both

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(D) $1$. Bayer's reagent $(1\% 	ext{ alkaline } KMnO_4)$ reacts with propene $(CH_3-CH=CH_2)$ to form propane$-1,2-$diol $(CH_3-CH(OH)-CH_2OH)$ as product $X$.$2$. Periodic acid $(HIO_4)$ is a glycol-cleaving agent that breaks vicinal diols into carbonyl compounds.$3$. The reaction is: $CH_3-CH(OH)-CH_2OH + HIO_4 ightarrow CH_3-CHO + HCHO + H_2O$.$4$. Thus,the products are acetaldehyde $(CH_3-CHO)$ and formaldehyde $(HCHO)$.

$CH_3-CH=CH_2$ $\xrightarrow[reagent]{\text{Bayer's}} X$ $\xrightarrow{HIO_4} \text{product},$
Product is

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$CH_3-CH=CH_2$ $\xrightarrow[reagent]{\text{Bayer's}} X$ $\xrightarrow{HIO_4} \text{product},$Product is