Identify the major product formed in the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reactant is $2,3-dibromobutane$. The reaction is a debromination reaction,which typically proceeds via an $E2$ mechanism using zinc dust

Vedclass · Accepted Answer

cis-but$-2-$ene

Vedclass · Answer

(A) The given reactant is $2,3-dibromobutane$. The reaction is a debromination reaction,which typically proceeds via an $E2$ mechanism using zinc dust $(Zn)$ in an alcoholic solvent.In the given Fischer projection,the two bromine atoms are on the same side (erythro form). When this specific stereoisomer undergoes $E2$ elimination,the hydrogen and bromine atoms must be in an anti-periplanar conformation.For the erythro$-2,3-$dibromobutane,the anti-elimination of $Br_2$ leads to the formation of $cis-but-2-ene$ as the major product.Therefore,the correct option is $A$.

Identify the major product formed in the following debromination reaction:
$CH_3-CH(Br)-CH(Br)-CH_3 \xrightarrow{-Br_2} \text{Major product}$

Similar Questions

$CH_3-CH=CH-CH=CH_2 \xrightarrow[Zn]{O_3 / H_2O}$ Which will not form?

Peroxide effect is observed with the addition of $HBr$ but not with the addition of $HI$ to unsymmetrical alkene because

$A$ compound '$X$' on ozonolysis forms two molecules of $HCHO$. Compound '$X$' is

Select the suitable reagent for the conversion shown below:

Which alkene on ozonolysis gives $CH_3CH_2CHO$ and $CH_3COCH_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the major product formed in the following debromination reaction:$CH_3-CH(Br)-CH(Br)-CH_3 \xrightarrow{-Br_2} \text{Major product}$