N_2 and O_2 are converted into N_2^+ and O_2^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Bond order $= 1/2 	imes (N_B - N_{AB})$.For $N_2$ ($14$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_x)^2(\pi 2p_

Vedclass · Accepted Answer

$N_2^+$ becomes diamagnetic

Vedclass · Answer

(D) Bond order $= 1/2 	imes (N_B - N_{AB})$.For $N_2$ ($14$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_x)^2(\pi 2p_y)^2(\sigma 2p_z)^2$. Bond order $= 1/2 	imes (10-4) = 3$.For $N_2^+$ ($13$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_x)^2(\pi 2p_y)^2(\sigma 2p_z)^1$. Bond order $= 1/2 	imes (9-4) = 2.5$. Since bond order decreases,the $N-N$ bond weakens.For $O_2$ ($16$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1(\pi^* 2p_y)^1$. Bond order $= 1/2 	imes (10-6) = 2$.For $O_2^+$ ($15$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1$. Bond order $= 1/2 	imes (10-5) = 2.5$. Since bond order increases,bond length decreases and paramagnetism decreases (from $2$ unpaired electrons to $1$).$N_2^+$ has $1$ unpaired electron,so it is paramagnetic,not diamagnetic. Thus,statement $D$ is incorrect.

$N_2$ and $O_2$ are converted into $N_2^+$ and $O_2^+$ respectively. Which of the following is not correct?

Similar Questions

According to the Molecular Orbital Theory,which of the following does not exist?

Which of the following statements is incorrect when $C_2$ changes to $C_2^{2-}$?

The number of paramagnetic species among the following is $......$
$B_{2}, Li_{2}, C_{2}, C_{2}^{-}, O_{2}^{2-}, O_{2}^{+},$ and $He_{2}^{+}$

Among $H_2, He_2^{+}, Li_2, Be_2, B_2, C_2, N_2, O_2^{-}$,and $F_2$,the number of diamagnetic species is (Atomic numbers: $H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9$)

$He_{2}$ molecule is not possible. Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module