What is the mass of glucose in 500 g of an a | vedclass

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(B) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Given: Molality $(m)$ = $0.5 \ mol/kg$,Mass of solvent $(W_{sol

Vedclass · Accepted Answer

$45$

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(B) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Given: Molality $(m)$ = $0.5 \ mol/kg$,Mass of solvent $(W_{solvent})$ = $500 \ g = 0.5 \ kg$.Number of moles of glucose $(n_{glucose})$ = $m 	imes W_{solvent} = 0.5 \ mol/kg 	imes 0.5 \ kg = 0.25 \ mol$.Molar mass of glucose $(C_6H_{12}O_6)$ = $(6 	imes 12) + (12 	imes 1) + (6 	imes 16) = 72 + 12 + 96 = 180 \ g/mol$.Mass of glucose = $n_{glucose} 	imes 	ext{Molar mass} = 0.25 \ mol 	imes 180 \ g/mol = 45 \ g$.

What is the mass of glucose in $500 \ g$ of an aqueous solution of glucose with a molality of $0.5 \ m$?

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