The hybridization of carbon in graphite and d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In graphite,each carbon atom is bonded to three other carbon atoms in a hexagonal planar structure,resulting in $sp^2$ hybridization.In diamond,ea

Vedclass · Accepted Answer

$sp^2, sp^3$

Vedclass · Answer

(B) In graphite,each carbon atom is bonded to three other carbon atoms in a hexagonal planar structure,resulting in $sp^2$ hybridization.In diamond,each carbon atom is bonded to four other carbon atoms in a tetrahedral geometry,resulting in $sp^3$ hybridization.Therefore,the hybridization of carbon in graphite and diamond is $sp^2$ and $sp^3$ respectively.

The hybridization of carbon in graphite and diamond is respectively ........

Similar Questions

In the acetylene molecule,the $C-H$ sigma bond is formed by the overlap of which orbitals?

In graphite,the $C$-atom is in which state of hybridisation?

In the formation of the $CH_4$ molecule,carbon makes use of:

The correct order of electronegativity of carbon in various hybridization states:

Hybridisation state of $C$ in diamond is

Vedclass Test Series

Exam Paper Generator

Online Exam Module