23 g of Na metal reacts with ethanol to prod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical reaction between sodium $(Na)$ and ethanol $(C_2H_5OH)$ is: $2C_2H_5OH + 2Na \rightarrow 2C_2H_5ONa + H_2$ From the stoichiometry of

Vedclass · Accepted Answer

$1/2$ mole of $H_2$

Vedclass · Answer

(C) The chemical reaction between sodium $(Na)$ and ethanol $(C_2H_5OH)$ is: $2C_2H_5OH + 2Na ightarrow 2C_2H_5ONa + H_2$ From the stoichiometry of the reaction,$2 	ext{ moles}$ of $Na$ produce $1 	ext{ mole}$ of $H_2$. Given mass of $Na = 23 \ g$. Molar mass of $Na = 23 \ g/mol$. Number of moles of $Na = \frac{23 \ g}{23 \ g/mol} = 1 	ext{ mole}$. Since $2 	ext{ moles}$ of $Na$ produce $1 	ext{ mole}$ of $H_2$,then $1 	ext{ mole}$ of $Na$ will produce $\frac{1}{2} 	ext{ mole}$ of $H_2$.

$23 \ g$ of $Na$ metal reacts with ethanol to produce which of the following?

Similar Questions

If $1$ mole of $N_2$ occupies a volume of $22.4 \, L$ at $NTP$,what is the density of $N_2$ in $g/L$?

If $V \ mL$ of a substance at $NTP$ weighs $W \ g$,then the molecular weight of the substance is....

Sulfur trioxide is prepared by the following reactions:
$S_{8(s)} + 8O_{2(g)} \to 8SO_{2(g)}$
$2SO_{2(g)} + O_{2(g)} \to 2SO_{3(g)}$
How many grams of $SO_3$ are obtained from $1 \ mol$ of $S_8$?

Hydrochloric acid solutions $A$ and $B$ have concentrations of $0.5 \,N$ and $0.1 \,N$ respectively. The volumes of solutions $A$ and $B$ required to make $2 \,L$ of $0.2 \,N$ hydrochloric acid are:

What is produced when $1 \ mol$ of calcium phosphide reacts with excess water?
$(Hint: Ca_3P_2 + H_2O (excess) \rightarrow Ca(OH)_2 + 2PH_3)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module