Determine the primary and secondary valency f | vedclass

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Question

(A) In the coordination compound $K_4[Fe(CN)_6]$,the central metal atom is $Fe$. The primary valency corresponds to the oxidation state of the central

Vedclass · Accepted Answer

Primary valency = $2$,Secondary valency = $6$

Vedclass · Answer

(A) In the coordination compound $K_4[Fe(CN)_6]$,the central metal atom is $Fe$. The primary valency corresponds to the oxidation state of the central metal atom. Let the oxidation state of $Fe$ be $x$. $4(+1) + x + 6(-1) = 0$ $4 + x - 6 = 0$ $x = +2$. Thus,the primary valency is $2$. The secondary valency corresponds to the coordination number,which is the number of ligand donor atoms directly bonded to the central metal atom. Here,$6$ $CN^-$ ligands are bonded to $Fe$,so the coordination number is $6$. Thus,the secondary valency is $6$.

Determine the primary and secondary valency for $K_4[Fe(CN)_6]$.

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[Given,atomic mass : $Co = 59, Cl = 35.5, Ag = 108$]

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