If frac{|x-1|}{x-1} leq 0,then x in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the inequality $\frac{|x-1|}{x-1} \leq 0$.For the expression to be defined,the denominator must not be zero,so $x - 1 
eq 0$,which implies

Vedclass · Accepted Answer

$(-\infty, 1)$

Vedclass · Answer

(A) Given the inequality $\frac{|x-1|}{x-1} \leq 0$.For the expression to be defined,the denominator must not be zero,so $x - 1 
eq 0$,which implies $x 
eq 1$.Case $1$: If $x > 1$,then $|x-1| = x-1$. The expression becomes $\frac{x-1}{x-1} = 1$. Since $1 
ot\leq 0$,there is no solution in this interval.Case $2$: If $x Therefore,the solution set is $x \in (-\infty, 1)$.

If $\frac{|x-1|}{x-1} \leq 0$,then $x \in$

Similar Questions

If $|x+2| \leq 9,$ then which of the following is true?

Solve the given inequality and show the graph of the solution on a number line:
$\frac{x}{2} \geq \frac{5x-2}{3} - \frac{7x-3}{5}$

Solve the given inequality for real $x$: $\frac{3(x-2)}{5} \leq \frac{5(2-x)}{3}$

If $|x-2| \geq |x-4|$ then $x \in \ldots$

Solve $30x < 200$ when $x$ is a natural number.

Vedclass Test Series

Exam Paper Generator

Online Exam Module