If p=9 and q=sqrt{17},then the value of (p^{2 | vedclass

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(B) Given: $p = 9$ and $q = \sqrt{17}$.We need to find the value of $(p^{2} - q^{2})^{\frac{-1}{3}}$.First,calculate $p^{2} = 9^{2} = 81$.Next,calcula

Vedclass · Accepted Answer

$\frac{1}{4}$

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(B) Given: $p = 9$ and $q = \sqrt{17}$.We need to find the value of $(p^{2} - q^{2})^{\frac{-1}{3}}$.First,calculate $p^{2} = 9^{2} = 81$.Next,calculate $q^{2} = (\sqrt{17})^{2} = 17$.Now,substitute these values into the expression: $p^{2} - q^{2} = 81 - 17 = 64$.The expression becomes $(64)^{\frac{-1}{3}}$.Since $64 = 4^{3}$,we can write this as $(4^{3})^{\frac{-1}{3}}$.Using the power rule $(a^{m})^{n} = a^{m 	imes n}$,we get $4^{3 	imes \frac{-1}{3}} = 4^{-1}$.$4^{-1} = \frac{1}{4}$.Thus,the correct option is $B$.

If $p=9$ and $q=\sqrt{17}$,then the value of $(p^{2}-q^{2})^{\frac{-1}{3}}$ is equal to

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