L.C.M. and H.C.F. of two numbers x and y are | vedclass

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(D) We know that for any two numbers $x$ and $y$,the product of the numbers is equal to the product of their $H.C.F.$ and $L.C.M.$$x 	imes y = H.C.F.

Vedclass · Accepted Answer

$\frac{4}{35}$

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(D) We know that for any two numbers $x$ and $y$,the product of the numbers is equal to the product of their $H.C.F.$ and $L.C.M.$$x 	imes y = H.C.F. 	imes L.C.M.$Given that $H.C.F. = 3$ and $L.C.M. = 315$,we have:$x 	imes y = 3 	imes 315 = 945$We need to find the value of $\frac{1}{x} + \frac{1}{y}$.$\frac{1}{x} + \frac{1}{y} = \frac{x + y}{x y}$Given $x + y = 36$,substitute the values:$\frac{1}{x} + \frac{1}{y} = \frac{36}{3 	imes 315}$Simplify the expression:$\frac{1}{x} + \frac{1}{y} = \frac{12}{315} = \frac{4}{35}$

$L.C.M.$ and $H.C.F.$ of two numbers $x$ and $y$ are $315$ and $3,$ respectively. If $x+y=36,$ the value of $\frac{1}{x}+\frac{1}{y}$ is

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