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(A) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $4$.The possible outc

Vedclass · Accepted Answer

$1:11$

Vedclass · Answer

(A) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event of getting a sum of $4$.The possible outcomes for the sum $4$ are $(1, 3), (3, 1), (2, 2)$.Thus,the number of favourable outcomes is $n(A) = 3$.The number of unfavourable outcomes is $36 - 3 = 33$.The odds in favour of an event are given by the ratio of favourable outcomes to unfavourable outcomes.Therefore,the odds in favour of getting a sum of $4 = \frac{3}{33} = \frac{1}{11}$,which is expressed as $1:11$.

$2$ dice are thrown. Find the odds in favour of getting the sum $4$.

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