3.65 g of HCl is dissolved in 16.2 g of wat | vedclass

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(D) The formula for mole fraction $(X)$ of a solute is $X = \frac{n}{n + N}$,where $n$ is the number of moles of solute and $N$ is the number of moles

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$0.1$

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(D) The formula for mole fraction $(X)$ of a solute is $X = \frac{n}{n + N}$,where $n$ is the number of moles of solute and $N$ is the number of moles of solvent.First,calculate the moles of $HCl$ $(n)$: $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{3.65 \ g}{36.5 \ g/mol} = 0.1 \ mol$.Next,calculate the moles of water $(N)$: $N = \frac{16.2 \ g}{18 \ g/mol} = 0.9 \ mol$.Finally,calculate the mole fraction of $HCl$: $X = \frac{0.1}{0.1 + 0.9} = \frac{0.1}{1.0} = 0.1$.

$3.65 \ g$ of $HCl$ is dissolved in $16.2 \ g$ of water. The mole fraction of $HCl$ in the resulting solution is

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