$9 \sec^{2} A - 9 \tan^{2} A = \dots$

If $\sin ^{2} 35^{\circ} + \cos ^{2} \theta = 1$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^{\circ}$)

If $\cos (\alpha+\beta)=0,$ then $\sin (\alpha-\beta)$ can be reduced to

If $A+B+C=180^{\circ},$ then $\tan \left(\frac{A+B}{2}\right)=$ ...........

The value of the expression $\left[\frac{\sin ^{2} 22^{\circ}+\sin ^{2} 68^{\circ}}{\cos ^{2} 22^{\circ}+\cos ^{2} 68^{\circ}}+\sin ^{2} 63^{\circ}+\cos 63^{\circ} \sin 27^{\circ}\right]$ is:

$(\sec A + \tan A)(1 - \sin A) = \dots$