Y- axis divides the line segment joining A(-3 | vedclass

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(C) Let the $Y-$ axis divide the line segment joining $A(-3, -4)$ and $B(1, -2)$ in the ratio $m:n$ at point $M(0, y)$.Since the point lies on the $Y-

Vedclass · Accepted Answer

$3:1$

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(C) Let the $Y-$ axis divide the line segment joining $A(-3, -4)$ and $B(1, -2)$ in the ratio $m:n$ at point $M(0, y)$.Since the point lies on the $Y-$ axis,its $x-$ coordinate is $0$.Using the section formula for the $x-$ coordinate: $x = \frac{mx_2 + nx_1}{m + n}$.Substituting the values: $0 = \frac{m(1) + n(-3)}{m + n}$.This implies $m - 3n = 0$,which gives $m = 3n$.Therefore,the ratio $\frac{m}{n} = \frac{3}{1}$,or $m:n = 3:1$.

$Y-$ axis divides the line segment joining $A(-3, -4)$ and $B(1, -2)$ from $A$ in the ratio............

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