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(B) To determine the nature of the given expression,we expand the product:$(x+6)(x+5) = x^2 + 5x + 6x + 30 = x^2 + 11x + 30$.Since the equation is giv

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quadratic equation

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(B) To determine the nature of the given expression,we expand the product:$(x+6)(x+5) = x^2 + 5x + 6x + 30 = x^2 + 11x + 30$.Since the equation is given as $(x+6)(x+5) = 0$,we can write it as $x^2 + 11x + 30 = 0$.An equation of the form $ax^2 + bx + c = 0$,where $a 
eq 0$,is defined as a quadratic equation.Since the highest power of the variable $x$ is $2$,it is a quadratic equation.

$(x+6)(x+5)=0$ is a ....... .

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