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(C) Given that $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$.By the property of similar triangles,the ratios of their

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$\frac{4}{5}$

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(C) Given that $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$.By the property of similar triangles,the ratios of their corresponding sides are equal.Therefore,$\frac{AB}{XY} = \frac{BC}{YZ} = \frac{AC}{XZ}$.From the given equation $\frac{AB}{4} = \frac{XY}{5}$,we can rearrange the terms to find the ratio $\frac{AB}{XY}$.Dividing both sides by $XY$ and multiplying by $4$,we get $\frac{AB}{XY} = \frac{4}{5}$.Since $\frac{BC}{YZ} = \frac{AB}{XY}$,it follows that $\frac{BC}{YZ} = \frac{4}{5}$.

If $\Delta ABC \sim \Delta XYZ$ for the correspondence $ABC \leftrightarrow XYZ$,and $\frac{AB}{4} = \frac{XY}{5}$,then $\frac{BC}{YZ} = \ldots$

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