If Delta ABC sim Delta MNP for the correspond | vedclass

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(B) Given that $\Delta ABC \sim \Delta MNP.$For similar triangles,the ratio of their perimeters is equal to the ratio of their corresponding sides.The

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$12$

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(B) Given that $\Delta ABC \sim \Delta MNP.$For similar triangles,the ratio of their perimeters is equal to the ratio of their corresponding sides.Therefore,$\frac{	ext{Perimeter of } \Delta ABC}{	ext{Perimeter of } \Delta MNP} = \frac{AB}{MN}.$Given: Perimeter of $\Delta ABC = 18,$ Perimeter of $\Delta MNP = 27,$ and $AB = 8.$Substituting the values: $\frac{18}{27} = \frac{8}{MN}.$Simplifying the fraction $\frac{18}{27}$ gives $\frac{2}{3}.$So,$\frac{2}{3} = \frac{8}{MN}.$$2 	imes MN = 8 	imes 3.$$2 	imes MN = 24.$$MN = \frac{24}{2} = 12.$Thus,$MN = 12.$

If $\Delta ABC \sim \Delta MNP$ for the correspondence $ABC \leftrightarrow MNP,$ the perimeter of $\Delta ABC$ is $18$ and the perimeter of $\Delta MNP$ is $27.$ If $AB = 8,$ then $MN = \dots$

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