$0.25 \ g$ of an organic compound containing chlorine gave $0.40 \ g$ of silver chloride in Carius estimation. The percentage of chlorine present in the compound is $.....$ [in nearest integer].
(Given: Molar mass of $Ag$ is $108 \ g \ mol^{-1}$ and that of $Cl$ is $35.5 \ g \ mol^{-1}$)

For the estimation of nitrogen,$1.4 \ g$ of an organic compound was digested by Kjeldahl method and the evolved ammonia was absorbed in $60 \ mL$ of $\frac{M}{10}$ sulphuric acid. The unreacted acid required $20 \ mL$ of $\frac{M}{10}$ sodium hydroxide for complete neutralization. The percentage of nitrogen in the compound is .....$\%$

Match Column-$I$ and Column-$II$ with the correct relation:

Column-$I$	Column-$II$
$(i).$ Magnesium pyrophosphate	$(a).$ $I_2O_5$
$(ii).$ Barium sulphate	$(b).$ $AgX$
$(iii).$ Iodide pentoxide	$(c).$ $Mg_2P_2O_7$
$(iv).$ Silver halide	$(d).$ $BaSO_4$

What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

$0.16 \ g$ of an organic compound containing sulphur produces $0.233 \ g$ of $BaSO_4$. The percentage of sulphur in the compound is:

When $0.15 \ g$ of an organic compound was analyzed using the Carius method for the estimation of bromine,$0.2397 \ g$ of $AgBr$ was obtained. The percentage of bromine in the organic compound is $.....$ (Nearest integer).
[Atomic mass: Silver $= 108$,Bromine $= 80$]