$NaCl$ reacts with conc. $H_2SO_4$ and $K_2Cr_2O_7$ to give reddish fumes $(B)$,which react with $NaOH$ to give yellow solution $(C)$. $(B)$ and $(C)$ respectively are:
- A$CrO_2Cl_2, Na_2CrO_4$
- B$Na_2Cr_2O_4, CrO_2Cl_2$
- C$CrO_2Cl_2, KHSO_4$
- D$CrO_2Cl_2, Na_2Cr_2O_7$
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