i^2 + i^4 + i^6 + dots up to (2n + 1) terms = | vedclass

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(D) The given expression is $i^2 + i^4 + i^6 + \dots$ up to $(2n + 1)$ terms.Since $i^2 = -1$,$i^4 = 1$,$i^6 = -1$,and so on,the series becomes $-1 +

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$-1$

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(D) The given expression is $i^2 + i^4 + i^6 + \dots$ up to $(2n + 1)$ terms.Since $i^2 = -1$,$i^4 = 1$,$i^6 = -1$,and so on,the series becomes $-1 + 1 - 1 + 1 - 1 + \dots$ up to $(2n + 1)$ terms.Since the number of terms $(2n + 1)$ is odd,the sum of the series is $-1 + (1 - 1) + (1 - 1) + \dots + (1 - 1) = -1 + 0 + 0 + \dots + 0 = -1$.Therefore,the correct option is $D$.

$i^2 + i^4 + i^6 + \dots$ up to $(2n + 1)$ terms =

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