$\frac{1^2 \cdot 2}{1!} + \frac{2^2 \cdot 3}{2!} + \frac{3^2 \cdot 4}{3!} + \dots \infty = $ ($e$ में)

  • A
    $6$
  • B
    $7$
  • C
    $8$
  • D
    $9$

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Similar Questions

$1 + \frac{3}{1!} + \frac{5}{2!} + \frac{7}{3!} + ....\infty = $

$(e^x - 1)(e^{-x} + 1)$ के विस्तार में,$x^3$ का गुणांक है

यदि $x=1+\frac{1}{2 \times 1 !}+\frac{1}{4 \times 2 !}+\frac{1}{8 \times 3 !}+\ldots$ और $y=1+\frac{x^{2}}{1 !}+\frac{x^{4}}{2 !}+\frac{x^{6}}{3 !}+\ldots$ है, तो $\log_{e} y$ का मान क्या है?

$\frac{1 \cdot 2}{1!} + \frac{2 \cdot 3}{2!} + \frac{3 \cdot 4}{3!} + \frac{4 \cdot 5}{4!} + \dots \infty = $

$1 + \frac{1 + 2}{2!} + \frac{1 + 2 + 3}{3!} + \frac{1 + 2 + 3 + 4}{4!} + \dots \infty = $

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