A magnetic dipole of magnetic moment M is fre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The potential energy $U$ of a magnetic dipole in an external magnetic field is given by the formula $U = -\vec{M} \cdot \vec{B} = -MB \cos 	heta$

Vedclass · Accepted Answer

$-MB, +MB$

Vedclass · Answer

(A) The potential energy $U$ of a magnetic dipole in an external magnetic field is given by the formula $U = -\vec{M} \cdot \vec{B} = -MB \cos 	heta$,where $	heta$ is the angle between the magnetic moment $\vec{M}$ and the magnetic field $\vec{B}$.For the minimum potential energy,$\cos 	heta$ must be maximum,which occurs at $	heta = 0^{\circ}$. Thus,$U_{	ext{min}} = -MB \cos 0^{\circ} = -MB(1) = -MB$.For the maximum potential energy,$\cos 	heta$ must be minimum,which occurs at $	heta = 180^{\circ}$. Thus,$U_{	ext{max}} = -MB \cos 180^{\circ} = -MB(-1) = +MB$.Therefore,the minimum and maximum values are $-MB$ and $+MB$ respectively.

$A$ magnetic dipole of magnetic moment $M$ is freely suspended in a magnetic field of induction $B$. The minimum and maximum values of the potential energy of the dipole,respectively,are

Similar Questions

Two identical short bar magnets are placed at $120^{\circ}$ as shown in the figure. The magnetic moment of each magnet is $M$. Then the magnetic field at the point $P$ on the angle bisector is given by

$A$ short bar magnet placed with its axis at $30^{\circ}$ with a uniform external magnetic field of $0.25 \; T$ experiences a torque of magnitude equal to $4.5 \times 10^{-2} \; J$. What is the magnitude of magnetic moment (in $J \; T^{-1}$) of the magnet?

$A$ short bar magnet placed with its axis at $30^{\circ}$ with a uniform external magnetic field of $0.25 \ T$ experiences a torque of magnitude $4.5 \times 10^{-2} \ J$. The magnitude of the magnetic moment of the magnet will be . . . . . . $J \ T^{-1}$.

Two small magnets, each of magnetic moment $10 \, A \cdot m^2$, are placed in an end-on position at a distance of $0.1 \, m$ apart from their centers. The force acting between them is .... $N$.

$A$ magnet of magnetic moment $20$ $C.G.S.$ units is freely suspended in a uniform magnetic field of intensity $0.3$ $C.G.S.$ units. The amount of work done in deflecting it by an angle of $30^{\circ}$ in $C.G.S.$ units is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module