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(B) Given: Radius $r = 100 \ m$,velocity $v = 20 \ m/s$,and tangential acceleration $a_{t} = 3 \ m/s^{2}$.First,calculate the radial (centripetal) acc

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$5$

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(B) Given: Radius $r = 100 \ m$,velocity $v = 20 \ m/s$,and tangential acceleration $a_{t} = 3 \ m/s^{2}$.First,calculate the radial (centripetal) acceleration $a_{r}$ using the formula $a_{r} = \frac{v^{2}}{r}$.$a_{r} = \frac{(20)^{2}}{100} = \frac{400}{100} = 4 \ m/s^{2}$.The resultant acceleration $a$ is the vector sum of the tangential and radial accelerations,which are perpendicular to each other.$a = \sqrt{a_{r}^{2} + a_{t}^{2}}$.$a = \sqrt{(4)^{2} + (3)^{2}} = \sqrt{16 + 9} = \sqrt{25} = 5 \ m/s^{2}$.Therefore,the resultant acceleration is $5 \ m/s^{2}$.

$A$ body is moving along a circular track of radius $100 \ m$ with velocity $20 \ m/s$. Its tangential acceleration is $3 \ m/s^{2}$,then its resultant acceleration will be (in $m/s^{2}$)

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