sin 50^circ - sin 70^circ + sin 10^circ = | vedclass

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(B) Using the formula $\sin C - \sin D = 2 \cos \frac{C+D}{2} \sin \frac{C-D}{2}$:$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ$$= 2 \cos \frac{50^\c

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(B) Using the formula $\sin C - \sin D = 2 \cos \frac{C+D}{2} \sin \frac{C-D}{2}$:$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ$$= 2 \cos \frac{50^\circ + 70^\circ}{2} \sin \frac{50^\circ - 70^\circ}{2} + \sin 10^\circ$$= 2 \cos 60^\circ \sin(-10^\circ) + \sin 10^\circ$$= -2 \cos 60^\circ \sin 10^\circ + \sin 10^\circ$$= -2 	imes \frac{1}{2} 	imes \sin 10^\circ + \sin 10^\circ$$= -\sin 10^\circ + \sin 10^\circ = 0.$

$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ = $

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