sin 50^circ - sin 70^circ + sin 10^circ = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $\sin C - \sin D = 2 \cos \frac{C+D}{2} \sin \frac{C-D}{2}$ સૂત્રનો ઉપયોગ કરતા:$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ$$= 2 \cos \frac{50^\

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) $\sin C - \sin D = 2 \cos \frac{C+D}{2} \sin \frac{C-D}{2}$ સૂત્રનો ઉપયોગ કરતા:$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ$$= 2 \cos \frac{50^\circ + 70^\circ}{2} \sin \frac{50^\circ - 70^\circ}{2} + \sin 10^\circ$$= 2 \cos 60^\circ \sin(-10^\circ) + \sin 10^\circ$$= -2 \cos 60^\circ \sin 10^\circ + \sin 10^\circ$$= -2 	imes \frac{1}{2} 	imes \sin 10^\circ + \sin 10^\circ$$= -\sin 10^\circ + \sin 10^\circ = 0.$

$\sin 50^\circ - \sin 70^\circ + \sin 10^\circ = $

Similar Questions

$\frac{\sin 55^{\circ} - \cos 55^{\circ}}{\sin 10^{\circ}}$ ની કિંમત શોધો.

$\frac{\sin x}{1+\cos x} + \frac{1+\cos x}{\sin x} = ?$

$\tan \left(1^{\circ}\right)+\tan \left(89^{\circ}\right)$ નું મૂલ્ય શું છે?

જો $y = \log_e \tan \left(\frac{\pi}{4} + \frac{x}{2}\right)$ હોય,તો $\tanh \left(\frac{y}{2}\right) = $

$\cos 1^\circ + \cos 2^\circ + \cos 3^\circ + \dots + \cos 180^\circ = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module