$A$ vessel of height $2d$ is half-filled with a liquid of refractive index $\sqrt{2}$ and the other half with a liquid of refractive index $n$ (the given liquids are immiscible). Then the apparent depth of the inner surface of the bottom of the vessel (neglecting the thickness of the bottom of the vessel) will be

  • A
    $\frac{n}{d(n+\sqrt{2})}$
  • B
    $\frac{d(n+\sqrt{2})}{n \sqrt{2}}$
  • C
    $\frac{\sqrt{2} n}{d(n+\sqrt{2})}$
  • D
    $\frac{n d}{d+\sqrt{2 n}}$

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