A vessel that can withstand a pressure of 100 | vedclass

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(C) Given that the volume of the vessel is constant, we use Gay-Lussac's Law, which states that $P \propto T$ for a fixed amount of gas.Initial pressu

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$1500$

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(C) Given that the volume of the vessel is constant, we use Gay-Lussac's Law, which states that $P \propto T$ for a fixed amount of gas.Initial pressure $P_1 = 20 \,atm$.Initial temperature $T_1 = 27^{\circ} C = 27 + 273 = 300 \,K$.Maximum pressure the vessel can withstand $P_2 = 100 \,atm$.Using the relation $\frac{P_1}{T_1} = \frac{P_2}{T_2}$, we find the temperature $T_2$ at which the vessel explodes:$T_2 = \frac{P_2 	imes T_1}{P_1} = \frac{100 \,atm 	imes 300 \,K}{20 \,atm} = 5 	imes 300 \,K = 1500 \,K$.

$A$ vessel that can withstand a pressure of $100 \,atm$ is filled with hydrogen at $27^{\circ} C$ up to a pressure of $20 \,atm$. If the vessel is heated, then the temperature at which it explodes is (in $\,K$)

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