(C) The force $F$ required to just move the body is equal to the limiting static friction force $f_s$.$f_s = \mu_s N = \mu_s mg$Given $\mu_s = 0.8$, $

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(C) The force $F$ required to just move the body is equal to the limiting static friction force $f_s$.$f_s = \mu_s N = \mu_s mg$Given $\mu_s = 0.8$, $m = 4 \,kg$, and $g = 10 \,ms^{-2}$.$F = 0.8 \times 4 \times 10 = 32 \,N$.Once the body starts moving, the kinetic friction force $f_k$ acts on it.$f_k = \mu_k N = \mu_k mg$Given $\mu_k = 0.6$.$f_k = 0.6 \times 4 \times 10 = 24 \,N$.The net force acting on the body is $F_{net} = F - f_k$.$F_{net} = 32 - 24 = 8 \,N$.Using Newton's second law, $F_{net} = ma$.$8 = 4 \times a$.$a = 2 \,ms^{-2}$.

Class 11 Physics Newton's Laws of Motion and Friction Static and Limiting Friction and Minimum Force Required to Move

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$A$ horizontal force just sufficient to move a body of mass $4 \,kg$ lying on a rough horizontal surface is applied on it. The coefficients of static and kinetic friction are $0.8$ and $0.6$ respectively. If the force continues to act even after the body has started moving, the acceleration of the body is (take $g=10 \,ms^{-2}$). (in $\,ms^{-2}$)

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$6$
B
$8$
C
$2$
D
$4$

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Class 11

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Newton's Laws of Motion and Friction

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Static and Limiting Friction and Minimum Force Required to Move

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In the figure shown,a block of weight $10 \, N$ is resting on a horizontal surface. The coefficient of static friction between the block and the surface is ${\mu _s} = 0.4$. $A$ force of $3.5 \, N$ will keep the block in uniform motion,once it has been set in motion. If a horizontal force of $3 \, N$ is applied to the block,then the block will:

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What is the maximum acceleration of a train such that a $50 \ kg$ box lying on its floor remains stationary (in $m \ s^{-2}$)? (Given: Coefficient of static friction between the box and the train's floor is $0.3$ and $g = 10 \ m \ s^{-2}$)

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