A hydraulic lift is shown in the figure. The | vedclass

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(B) Given radii of pistons are $r_1 = 2 \ m$ and $r_2 = 5 \ m$. Let $m_1$ be the mass placed on piston $P_1$ and $m_2 = x$ be the mass placed on pisto

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$0.16$

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(B) Given radii of pistons are $r_1 = 2 \ m$ and $r_2 = 5 \ m$. Let $m_1$ be the mass placed on piston $P_1$ and $m_2 = x$ be the mass placed on piston $P_2$.According to Pascal's law,the pressure at the same horizontal level in a continuous static fluid is the same.$p_1 = p_2$$\frac{F_1}{A_1} = \frac{F_2}{A_2}$Since $F = mg$ and $A = \pi r^2$,we have:$\frac{m_1 g}{\pi r_1^2} = \frac{m_2 g}{\pi r_2^2}$$\frac{m_1}{r_1^2} = \frac{m_2}{r_2^2}$Substituting the given values:$\frac{m_1}{2^2} = \frac{x}{5^2}$$\frac{m_1}{4} = \frac{x}{25}$$m_1 = \frac{4}{25} x = 0.16 x$Thus,the minimum mass that should be kept on $P_1$ is $0.16 x$.

$A$ hydraulic lift is shown in the figure. The radii of the movable pistons $P_1$ and $P_2$ are $2 \ m$ and $5 \ m$ respectively. If a block of mass $x$ is placed on $P_2$,then the minimum mass that should be kept on $P_1$ to lift the block on $P_2$ is (in $x$)

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