$A$ solid sphere of radius $R$ carries a positive charge $Q$ distributed uniformly throughout its volume. $A$ very thin hole is drilled through its center. $A$ particle of mass $m$ and charge $-q$ performs simple harmonic motion about the center of the sphere in this hole. The frequency of oscillation is

  • A
    $\frac{1}{2 \pi}\left[\frac{Q q}{4 \pi \varepsilon_0 R^3 m}\right]^{\frac{1}{2}}$
  • B
    $\frac{1}{2 \pi}\left[\frac{Q q}{4 \pi \varepsilon_0 R^2 m}\right]^{\frac{1}{2}}$
  • C
    $\frac{1}{2 \pi} \frac{Q}{\left[4 \pi \varepsilon_0 m R^3\right]^{-\frac{1}{2}}}$
  • D
    $\frac{1}{2 \pi}\left[\frac{Q q}{4 \pi \varepsilon_0 m R}\right]^{\frac{1}{2}}$

Explore More

Similar Questions

The number of electrons to be put on a spherical conductor of radius $0.1\,m$ to produce an electric field of $0.036\,N/C$ just above its surface is:

Four charges are placed on the corners of a square as shown in the figure,with a side length of $5 \, cm$. If $Q = 1 \, \mu C$,then the electric field intensity at the centre will be:

Difficult
View Solution

In the figure shown,the distance from point $A$ to the point where the electric field intensity is zero is .......... $cm$.

Difficult
View Solution

Two charges $Q$ are placed at two vertices of an equilateral triangle of side $a$. What is the electric field at the third vertex?

Difficult
View Solution

In the given figure,the electric field at the center $O$ due to section $AB$ of a uniformly charged ring is $\overrightarrow{E}$. What will be the electric field at $O$ due to the remaining section $ACB$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo